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Math Help - equation

  1. #1
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    equation

    a^2(x-1)-9=a(3x-6)
    x*a(a-3)=a^2-6a+9
    x*a(a-3)=(a-3)^2
    x=\frac{(a-3)^2}{a(a-3)}

    Now... I am sure that solutioin is not defined for a=0, but can I reduce the fraction to:
    x=\frac{(a-3)}{a},
    without any notes, or do I have to state that reduction of fraction is only posible for a not equal 3? Or in other words, is a=3 also a solution?
    Last edited by riki_haj; January 7th 2007 at 10:30 PM.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by riki_haj View Post
    a^2(x-1)-9=a(3x-6)
    x*a(a-3)=a^2-6a+9
    x*a(a-3)=(a-3)^2
    x=\frac{(a-3)^2}{a(a-3)}

    Now... I am sure that solutioin is not defined for a=0, but can I reduce the fraction to:
    x=\frac{(a-3)}{a},
    without any notes, or do I have to state that reduction of fraction is only posible for a not equal 3? Or in other words, is a=3 also a solution?
    Look at the original equation, you will see that it is inconsistent when a=3.
    So you know that if there is a solution a!=3, and you can do the cancellation.
    But you should say so.

    RonL
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