I have an inequality. 3 - 3(x-2) > 0 So i am quite unsure about how to do these we have only covered them once so please let me know if/when I go wrong. 3 - 3x +6 > 0 Move 6 over. 3 - 3x >6 Move 3 over. 3x > 9 x > 3 ??? Hows that?
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Originally Posted by el123 I have an inequality. 3 - 3(x-2) > 0 So i am quite unsure about how to do these we have only covered them once so please let me know if/when I go wrong. 3 - 3x +6 > 0 Move 6 over. 3 - 3x >6 Move 3 over. 3x > 9 x > 3 ??? Hows that? Not quite. You've got some sign issues $\displaystyle 3-3(x-2)>0$ $\displaystyle 3-3x+6>0$ $\displaystyle 3-3x>-6$ $\displaystyle -3x>-9$ $\displaystyle x<3$
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