Solve for x:

(x^2 - 4x + 4x - 16) - (x^2 - 2x - 3x + 6) = 0

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- July 31st 2009, 05:10 PMmarie7Algebra question
Solve for x:

(x^2 - 4x + 4x - 16) - (x^2 - 2x - 3x + 6) = 0 - July 31st 2009, 05:18 PMChris L T521
- July 31st 2009, 05:21 PMmarie7
So it would be -5x -10 = 0 right? Then where would I go from there? Because the question I'm doing are quadratic equations and then there's this one which is random and doesn't have the format to do a quadratic calculation on it.

- July 31st 2009, 05:23 PMmarie7
-5x = 10

x = -2 is the answer I've gotten.

The original equation is [(x + 4) / (x +2)] - [(x - 3) / (x - 4)] = 0 and I simplified it to the equation I mentioned in my first post. -2 doesn't fit into the original equation. Maybe I've done something wrong. - July 31st 2009, 05:27 PMChris L T521
- July 31st 2009, 05:29 PMmarie7
I thought -16 + 6 is -10? not -22

- July 31st 2009, 05:32 PMChris L T521
- July 31st 2009, 05:34 PMmarie7
I'll copy and paste this just in case you didn't see it in my above post:

"The original equation is [(x + 4) / (x +2)] - [(x - 3) / (x - 4)] = 0 and I simplified it to the equation I mentioned in my first post. your answer doesn't fit into the original equation. Maybe I've done something wrong in my calculations."

Note that I've just edited the first (x - 4) to (x +4) in the equation above. It was a typo, so sorry! - July 31st 2009, 05:42 PMChris L T521
- July 31st 2009, 05:45 PMmarie7
Thank you very much for your help! *gives you cookies*