Show how the expression (-2i+1) is equivalent to (3-i)/(1+i)
= (3-i)x(1-i) / (1+i)x(1-i)
= (3i-3-i^2+1) / (i^2-1)
What is next
Thanks in advance
I wince when I see that. -1, like any complex number except 0, has two square roots. Unlike real numbers, since the complex numbers do not form and ordered field, we cannot just say "the positive number such that". I prefer just to assert that $\displaystyle i^2= -1$ and leave it at that. There are ways to define the complex numbers that avoid that problem.