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Math Help - Algebra 2 problems.

  1. #1
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    Algebra 2 problems.

    Solve each equation.

    1. x - 1 = √(x+2) + 3


    2. 2x^2 - 6x + 5 = 0



    I'm not sure how to do these?
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  2. #2
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    Quote Originally Posted by garbles View Post
    Solve each equation.

    1. x - 1 = √(x+2) + 3


    2. 2x^2 - 6x + 5 = 0



    I'm not sure how to do these?
    The 2nd equation is a quadratic. Use the formula to solve it.

     x - 1 = \sqrt{x+2} + 3

     x - 4 = \sqrt{x+2} and x\geq -2

    Now square both sides:

    x^2-8x+16=x+2

    You have again a quadratic. Solve it for x.

    You'll get 2 solutions which are both valid.
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  3. #3
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    Lets start by doing some rearranging:

    x-1=\sqrt{(x+2)}+3 can be rearranged as

    x-1-3=\sqrt{x+2}

    I can then take the square of both side (to get rid of that pesky squareroot)

    (x-4)^{2}=(\sqrt{x+2})^{2}

    Can you take it from there?

    You will not get a perfect factor and will have to use the quadratic formula to find a solution. The same holds true for your second problem.
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  4. #4
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    Yeah I should be able to get it from there thanks.
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