I cannot get the correct answer of this problem. The answer is 445 but I got 435. May be I didn't understand what the last sentence meant.
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Originally Posted by shrrikesh I cannot get the correct answer of this problem. The answer is 445 but I got 435. May be I didn't understand what the last sentence meant. It is a trick. Find these values: . Do you now see where the extra 10 comes from?
Originally Posted by shrrikesh I cannot get the correct answer of this problem. The answer is 445 but I got 435. May be I didn't understand what the last sentence meant. I got 435 too - perhaps they're somehow rounding it differently? edit: found it... those dastardly so and sos...
Originally Posted by Unenlightened I got 435 too - perhaps they're somehow rounding it differently? edit: plato - did you get a different answer? The answer is 445. That is 30 integers 1 to 29 with two 10's.
I feel cheated
445 is correct. If n=10: |190/19| = 10 If n=11: |219/20| = 10 Missed one of those? Your answer of 435 is sum of digits from 1 to 29 ; 29*(30/2) = 435. So you're missing a term, since you need 30 terms.
Originally Posted by shrrikesh I cannot get the correct answer of this problem. The answer is 445 but I got 435. May be I didn't understand what the last sentence meant. First, make a simple conversion Therefore, we consider two cases: 1) if then . 2) if then . So we have . Finally we have
Last edited by DeMath; Jul 29th 2009 at 01:55 PM. Reason: refinement
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