Thread: Solve and graph?

y=|x|-5
3x-1=6x+y

so confused. please help.

Originally Posted by sonataplease

...so confused. please help.

Me too. Are trying to solve the system of the two equations. Or are you tryin to solve each independently?

This could help

Originally Posted by VonNemo19

Me too. Are trying to solve the system of the two equations. Or are you tryin to solve each independently?

This could help

sorry, shoulda specified... independently.

I am afraid I don't understand the equations you posted either. I am horrid at math.

Originally Posted by sonataplease

sorry, shoulda specified... independently.

I am afraid I don't understand the equations you posted either. I am horrid at math.

Well, then, there is no way to "solve" these equations because there are two variables (x and y). But we CAN graph them.

If you look at my last post, you'll see that I "broke up" the first equation into two seperate equations. If you sketch the graph, it'll look like a v.

Originally Posted by VonNemo19

Well, then, there is no way to "solve" these equations because there are two variables (x and y). But we CAN graph them.

If you look at my last post, you'll see that I "broke up" the first equation into two seperate equations. If you sketch the graph, it'll look like a v.

I see... The second equation... how do I go about figuring that one? I graphed the first, did get a v.

Originally Posted by sonataplease

I see... The second equation... how do I go about figuring that one? I graphed the first, did get a v.

Solve for y:









You can see that this is a linear equation of the form , where is the slope of the line, and is the y-intercept.

You can use the y-intercept along with the slope of the line to sketch the graph. Or you could use the y-intercept along with another point (ie (1,-4)) to draw the graph. Either way is fine.

Originally Posted by VonNemo19

Solve for y:









You can see that this is a linear equation of the form , where is the slope of the line, and is the y-intercept.

You can use the y-intercept along with the slope of the line to sketch the graph. Or you could use the y-intercept along with another point (ie (1,-4)) to draw the graph. Either way is fine.

THANK YOU!!!