1. ## A little bit of help is needed please!

I have a problem that I answered using logic, but I can't get figure out the working for it.

The question is:
Solve using the five step method.
When the digits of a two-digit number are reversed, the new number is 9 more than the original, and the sum of the digits of the original number is 11. What is the original number?

My process: There are only a few numbers that add up to 11: 1+10, 2+9, 3+8, etc. However, only one of these pairs are consecutive, and only consecutive numbers behave as described in the question when reversed(e.g. 34 and 43, 67 and 76 and so on). Thus the answer is 56.

Drakmord

2. Originally Posted by drakmord
I have a problem that I answered using logic, but I can't get figure out the working for it.

The question is:
Solve using the five step method.
When the digits of a two-digit number are reversed, the new number is 9 more than the original, and the sum of the digits of the original number is 11. What is the original number?

My process: There are only a few numbers that add up to 11: 1+10, 2+9, 3+8, etc. However, only one of these pairs are consecutive, and only consecutive numbers behave as described in the question when reversed(e.g. 34 and 43, 67 and 76 and so on). Thus the answer is 56.

Drakmord
That looks great to me!

3. Originally Posted by drakmord
I have a problem that I answered using logic, but I can't get figure out the working for it.

The question is:
Solve using the five step method.
When the digits of a two-digit number are reversed, the new number is 9 more than the original, and the sum of the digits of the original number is 11. What is the original number?