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Math Help - Equation in RR

  1. #1
    Super Member dhiab's Avatar
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    Equation in RR

    Solve in RR this equation :
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  2. #2
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    Quote Originally Posted by dhiab View Post
    Solve in RR this equation :

    real numbers x real numbers ?
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  3. #3
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    Quote Originally Posted by dhiab View Post
    Solve in RR this equation :
    R \times R is, technically, the set of ordered pairs of real numbers which have no multiplication or addition defined on them. I thought you meant the vector space R^2. But in that case \sqrt{a^2+ b^2} is a number while a+ b is a vector. Please explain what you mean by this question.

    Are you asking for two real numbers, a and b, such that \sqrt{a^2+ b^2}= a+ b? In that case, a any non-negative real number and b= 0 is a solution.
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  4. #4
    Super Member dhiab's Avatar
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    Quote Originally Posted by mathaddict View Post
    real numbers x real numbers ?
    Hello : FIND (a,b) a and b reals numbers.
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  5. #5
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    Quote Originally Posted by dhiab View Post
    Hello : FIND (a,b) a and b reals numbers.

    ok .

    a^2+b^2=a^2+2ab+b^2

    2ab=0

    ab=0 .. then this is pretty obvious , one of it must be 0 .

    Either a belongs to R^+ , b=0 or the other way round .
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  6. #6
    Super Member dhiab's Avatar
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    thank you for the details solutions.
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  7. #7
    Super Member dhiab's Avatar
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    Quote Originally Posted by mathaddict View Post
    ok .

    a^2+b^2=a^2+2ab+b^2

    2ab=0

    ab=0 .. then this is pretty obvious , one of it must be 0 .

    Either a belongs to R^+ , b=0 or the other way round .
    HELLO ,THANK YOU
    I'have anathor details :
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