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  1. #1
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    Don't understand the question?

    If [14x / root(2x+2)], what is one possible value of x?

    14x / root(2x+2) is a term not an equation!

    I don't know how to figure it out..

    The answer to this was 1/2
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  2. #2
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    Quote Originally Posted by juliak View Post
    If [14x / root(2x+2)], what is one possible value of x?

    14x / root(2x+2) is a term not an equation!

    I don't know how to figure it out..

    The answer to this was 1/2
    There is something missing from the question.
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  3. #3
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    Have you posted the whole question?
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  4. #4
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    well

    IF x = 1/2, then your expression must equal 7 / sqrt(3):
    14x / sqrt(2x + 2) = 7 / sqrt(3)
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    Quote Originally Posted by juliak View Post
    If [14x / root(2x+2)], what is one possible value of x?
    possible domain question?

    x can be any value such that 2x+2 > 0
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  6. #6
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    Quote Originally Posted by juliak View Post
    If [14x / root(2x+2)], what is one possible value of x?
    Well, one possible value is x= 0! A more interesting question is "what are all the possible values of x.

    14x / root(2x+2) is a term not an equation!
    That's true, but irrelevant. This problem did say anything about "solving an equation".

    I don't know how to figure it out..

    The answer to this was 1/2
    No, an answer was 1/2. If x= 1/2 then \frac{14x}{\sqrt{2x+2}}= \frac{14(1/2)}{\sqrt{2(1/2)+ 2}}= \frac{7}{\sqrt{3}} which is a perfectly good result. x can be 1/2. If x= 0, as I gave before, then
    \frac{14x}{\sqrt{2x+2}}= \frac{14(0)}{\sqrt{2(0)+ 2}}= \frac{0}{\sqrt{2}}= 0 which is also a valid answer. Or x= 1000000 (for no paticular reason) then \frac{14x}{\sqrt{2x+2}}= \frac{14(1000000)}{\sqrt{2(1000000)+ 2}}= \frac{14000000}{\sqrt{2000002}} which is again a perfectly good result. There are, literally, an infinite number of possible answers to this problem.

    (But not all numbers. For example, if x= -1, that denominator becomes \sqrt{2(-1)+ 1}= 0 and you cannot divide by 0. If x= -2, you have \sqrt{2(-2)+ 1}= \sqrt{-3}, not a real number.)
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