how would you do that for "i" and "1-3i" it says to find the recepricol of each and put it in a + bi form
Follow Math Help Forum on Facebook and Google+
$\displaystyle \frac{1}{i}=\frac{-i}{-i^2}=-i$ $\displaystyle \frac{1}{1-3i}=\frac{1+3i}{(1-3i)(1+3i)}=\frac{1+3i}{10}=\frac{1}{10}+\frac{3}{1 0}i$
View Tag Cloud