I need help with these just cant figure them out

1. 3^(?) =1

2. 3^(?) = 1/3

3.log5 (1/25) =?

4. logx = -0.7

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- Jul 20th 2009, 08:09 PMicecreamfrk09Logarithms :(
I need help with these just cant figure them out

1. 3^(?) =1

2. 3^(?) = 1/3

3.log5 (1/25) =?

4. logx = -0.7 - Jul 20th 2009, 08:17 PMpickslides
- Jul 20th 2009, 08:27 PMpickslides
- Jul 20th 2009, 08:28 PMicecreamfrk09
thank you both...so both one and two are the same answer??

- Jul 20th 2009, 08:32 PMTKHunny
What? How did you draw that conclusion? These are the most fundamental properties. You must know these or you WILL fail your exams.

$\displaystyle 3^{1} = 3$

$\displaystyle 5^{1} = 5$

$\displaystyle 4^{0} = 1$

$\displaystyle 6^{0} = 1$

$\displaystyle 2^{-1} = 1/2$

$\displaystyle 7^{-1} = 1/7$

Look at these until you no longer feel an urge to ask the question about 1 and 2 being the same. - Jul 20th 2009, 08:36 PMpickslides
- Jul 20th 2009, 08:46 PMicecreamfrk09
k thank you tkhunny i understand now

- Jul 20th 2009, 08:48 PMyeongil
To expand on this,

$\displaystyle 3^{1} = 3$ because $\displaystyle \log_3 3 = 1$

$\displaystyle 5^{1} = 5$ because $\displaystyle \log_5 5 = 1$

$\displaystyle 4^{0} = 1$ because $\displaystyle \log_4 1 = 0$

$\displaystyle 6^{0} = 1$ because $\displaystyle \log_6 1 = 0$

$\displaystyle 2^{-1} = 1/2$ because $\displaystyle \log_2 \left(\frac{1}{2}\right) = -1$

$\displaystyle 7^{-1} = 1/7$ because $\displaystyle \log_7 \left(\frac{1}{7}\right) = -1$

01 - Jul 21st 2009, 08:33 PMTKHunny