1. if x=2 2. if x=5 3. if x=-2 4. if n=2.78 5. to solve you must use the logarithmic method
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Originally Posted by william 1. if x=2 <<< No 2. if x=5 <<< No 3. if x=-2 <<< No 4. if n=2.78 <<< No 5. to solve you must use the logarithmic method How did you do these calculations? Obviously you need a lot of help. But we must know where and why you've made the mistakes. Otherwise we can't help you sufficiently. I'll take #5:
Originally Posted by earboth How did you do these calculations? Obviously you need a lot of help. But we must know where and why you've made the mistakes. Otherwise we can't help you sufficiently. I'll take #5: new answers for 1. x=2 2. x=-3 3. x=2 4. n=0.30
Originally Posted by william 1. if x=2 2. if x=5 3. if x=-2 4. if n=2.78 5. to solve you must use the logarithmic method Originally Posted by william new answers for 1. x=2 2. x=-3 3. x=2 4. n=0.30 No, x still isn't 2. In this case note that 27 = 3^3 2. Yes 3. Yup 4. nay Divide both sides through by 300:
Originally Posted by william new answers for 1. x=2 ... You can check yourself if you've got the correct solution: Plug in the value of x into the original equation. If you get the same value on both sides of the equation your solution is OK. If not then ... plug in x = 2 (that's your solution!): Thus your result is wrong.
Originally Posted by e^(i*pi) No, x still isn't 2. In this case note that 27 = 3^3 2. Yes 3. Yup 4. nay Divide both sides through by 300: so 1. x=3 4. x=14.21
Originally Posted by william so 1. x=3 4. x=14.21 To check do what earboth suggested in post 5 but I get those from my calculations
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