please help me i dont remember how to do these anymore

1. add (1/x+3) + (5/x-4)

2. subtract (3/x) - (7/x-2)

3. subract (3/x-3) - (4/x+5)

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- Jul 19th 2009, 08:40 PMicecreamfrk09help please with adding and subtracting rational expressions
please help me i dont remember how to do these anymore

1. add (1/x+3) + (5/x-4)

2. subtract (3/x) - (7/x-2)

3. subract (3/x-3) - (4/x+5) - Jul 19th 2009, 08:43 PMAlephZero
- Jul 19th 2009, 08:46 PMicecreamfrk09
the second one please and im sorry im new to this website

- Jul 19th 2009, 08:55 PMAlephZero
- Jul 19th 2009, 09:03 PMicecreamfrk09
thank you so much but how to you subtract the rational expressions?

- Jul 19th 2009, 09:11 PMAlephZero
- Jul 19th 2009, 09:17 PMAlephZero
By the way, and not to be a stick-in-the-mud, but you're still not expressing these in a mathematically correct way, which is important because it's hard for us to tell what you mean. The correct way to use the parentheses would be

1. 1/(x+3) + 5/(x-4)

2. 3/x - 7/(x-2)

3. 3/(x-3) - 4/(x+5)

In other words, you need to group all the numerators and denominators together, so we know what is being divided into what. I hope that makes sense. - Jul 19th 2009, 09:19 PMicecreamfrk09
okayy not sure if i did these right but i got (3-7x)/x for the second one and -1 for the third one is that right??

- Jul 19th 2009, 09:26 PMAlephZero
- Jul 19th 2009, 09:41 PMicecreamfrk09
okayy i got (-4x-6)/x(x-2) for the second and (-x+27)/(x+5)(x-3) for the third but do you multiply the denominator for third one?

- Jul 19th 2009, 09:43 PMyeongil
No, you can leave the denominator in factored form. It's considered to in "simplified form" that way.'

01 - Jul 19th 2009, 09:47 PMicecreamfrk09
okayy so both those answers are right?

- Jul 19th 2009, 09:55 PMAlephZero