How to I solve the following for x?
x^-0.6 = 36
Thanks.
Think about which number you need to make -0.6 get to 1 and then raise it by that number as well as the 36
$\displaystyle (x^{-\frac{3}{5}})^{-\frac{5}{3}} = x^1 = x = 36^{-\frac{5}{3}}$
Note this is not a rational number so it should be acceptable to leave the right hand side like that