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**A Beautiful Mind** Alright, I just got some ridiculously long five page answer that ended up with imaginary numbers as the answer.

I think the problem is a bit more simple than what I used that's usually a dependable program to figure out an answer...

$\displaystyle \sqrt{x^2-4x+9-x}=-1$

$\displaystyle \sqrt{x^2-4x+9-x+x}=-1+x$

$\displaystyle \sqrt{x^2-4x+9}=0$

Get rid of the square root sign and voila...

$\displaystyle x-2+3=0$

$\displaystyle x+1=0$

$\displaystyle x-1=0-1$

$\displaystyle x=-1$

Which is the correct answer. Was my method unorthodox or a coincidence or what?

EDIT: This is not actually the right answer...the answer is x=4?

Someone help?