Originally Posted by

**angypangy** This is the question:

A strand of wire of length 32cm is cut into two pieces. One piece is bent to form a rectangle of width x cm and length (x + 2) cm, and the other piece is bent to form a square.

A) show that the square has sides of length (7 - x) cm.

rectangle perimeter = 2[x + (x+2)] = 2x + 2(x+2) = 4x + 4

square perimeter = 32 - (4x + 4) = 28 - 4x

square side = (28 - 4x)/4 = 7 - x

B) given that the total of the areas enclosed by both the rectangle and the square is 31cm2., form an equation for x and solve t to find the value of x.

x(x+2) + (7-x)^2 = 31

solve for x