...This is the question:
A strand of wire of length 32cm is cut into two pieces. One piece is bent to form a rectangle of width x cm and length (x + 2) cm, and the other piece is bent to form a square.
A) show that the square has sides of length (7 - x) cm.
rectangle perimeter = 2[x + (x+2)] = 2x + 2(x+2) = 4x + 4
square perimeter = 32 - (4x + 4) = 28 - 4x
square side = (28 - 4x)/4 = 7 - x
B) given that the total of the areas enclosed by both the rectangle and the square is 31cm2., form an equation for x and solve t to find the value of x.
x(x+2) + (7-x)^2 = 31
solve for x