I need to rationalize: 9 cuberoot of 2 over cuderooot of 5 - cuberoot of 2

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- Jul 15th 2009, 02:22 PMkandela573how do i start
I need to rationalize: 9 cuberoot of 2 over cuderooot of 5 - cuberoot of 2

- Jul 15th 2009, 02:29 PMPlato
Recall that .

- Jul 15th 2009, 02:38 PMkandela573
okay but in order for it to be simplified i can't have a radicand in the denominator so do i mulitply everything by the third power?(Thinking)

- Jul 15th 2009, 02:59 PMVonNemo19
- Jul 15th 2009, 03:41 PMPlato