Results 1 to 3 of 3

Math Help - Newton-Raphson

  1. #1
    Newbie
    Joined
    Nov 2007
    Posts
    9

    Newton-Raphson

    solve the equation completely:
    4iz^3 + iz + 6 + 22i = 0 where i=(-1)^0.5
    use a starting value of z initial = 1 + i


    THANKS
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member
    Joined
    Jul 2009
    From
    Singapore
    Posts
    338
    Quote Originally Posted by summna09 View Post
    solve the equation completely:
    4iz^3 + iz + 6 + 22i = 0 where i=(-1)^0.5
    use a starting value of z initial = 1 + i


    THANKS
    i don't think you can have a number \sqrt{-1}
    is this the whole question?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by summna09 View Post
    solve the equation completely:
    4iz^3 + iz + 6 + 22i = 0 where i=(-1)^0.5
    use a starting value of z initial = 1 + i


    THANKS
    Where are you stuck in applying the algorithm?

    Are you trying to create a fractal?

    Quote Originally Posted by arze View Post
    i don't think you can have a number \sqrt{-1}
    is this the whole question?
    Newton-Raphson works exactly the same in complex analysis as it does in real analysis - same derivatives, same formula ....
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Newton Raphson
    Posted in the Calculus Forum
    Replies: 2
    Last Post: November 12th 2010, 03:42 AM
  2. Newton-Raphson
    Posted in the Calculus Forum
    Replies: 1
    Last Post: May 12th 2009, 04:06 AM
  3. newton raphson
    Posted in the Calculus Forum
    Replies: 1
    Last Post: December 17th 2008, 05:23 AM
  4. Newton-Raphson
    Posted in the Calculus Forum
    Replies: 4
    Last Post: April 30th 2008, 06:40 AM
  5. newton Raphson
    Posted in the Calculus Forum
    Replies: 2
    Last Post: October 15th 2007, 11:43 PM

Search Tags


/mathhelpforum @mathhelpforum