OK, I have a good feeling it's going to turn into a complex trinomial.
By substituting with a variable, say "z"
That would give us..
Still not a trinomial..hmm
I see that the factor may be, -1 and 32.
Or, do I somehow break down the 4 into . But still the exponent 2 would not be over the z.
I've used that before. =]
That fraction is REALLY throwing me off..
Next, I think you divide the both sides by log2?
Or do I get the values, like:
It sorta works, and when subbed into the original equation it equals 0.00156
There must be a better way..
When you take the log of a fraction, the value is negative.
So it is ok to right the solution as . Now by change of base formula , we can rewrite our solution as .
Now when you plug it into verify the solution, we keep in mind that :
So it shows that is the solution to our equation.
So, if you substitute with another variable (I'll use y), you would get
I'd double check wherever you got the problem to make sure that the exponents are correct.