The square matrix X is such that X^3 = 0. Show that the inverse of the matrix (I - X) is I + X + X^2.
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EDIT : I don't why it keeps making it lowercase.
You should probably also show that (I+X+X^2)(I-X) = I
Originally Posted by Random Variable EDIT : I don't why it keeps making it lowercase. Type [tex]\mathcal{X}[/tex] to get .
Originally Posted by Plato Type [tex]\mathcal{X}[/tex] to get . Why is it converted to lowercase sometimes? I guess I could also use
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