I was given an equation and asked to solve for C. I've been able to simplify it to

B(AC)=A-C

I can't seem to get any further. Can anyone offer some suggestions?

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- Jul 10th 2009, 06:08 AMvorsilvaPlease help. Trying to isolate a variable and I'm stuck.
I was given an equation and asked to solve for C. I've been able to simplify it to

B(AC)=A-C

I can't seem to get any further. Can anyone offer some suggestions? - Jul 10th 2009, 06:12 AMcolby2152
You need to break the variable out of the multiple term on the LHS...

$\displaystyle BAC=A-C$

$\displaystyle C(BA)=A-C$

Now, group the terms with C's on one side, and the terms without C's on the other side.

$\displaystyle C(BA)+C=A$

Factor out C on the LHS, and divide the equality by the other factor, and you will get your answer. Practice this with many other forms of multiples, divisions, additions, and subtractions. - Jul 10th 2009, 06:15 AMallyourbass2212
Would that be

$\displaystyle C(BA-1)=A$

$\displaystyle

C=\frac{A}{BA+1}$

Thanks Skeeter - Jul 10th 2009, 06:58 AMskeeter
- Jul 10th 2009, 12:10 PMcolby2152
- Jul 10th 2009, 12:14 PMUnenlightened
Edit: Seems question had already been answered but only the original post was showing up for me! Apols..