I was given an equation and asked to solve for C. I've been able to simplify it to
B(AC)=A-C
I can't seem to get any further. Can anyone offer some suggestions?
You need to break the variable out of the multiple term on the LHS...
$\displaystyle BAC=A-C$
$\displaystyle C(BA)=A-C$
Now, group the terms with C's on one side, and the terms without C's on the other side.
$\displaystyle C(BA)+C=A$
Factor out C on the LHS, and divide the equality by the other factor, and you will get your answer. Practice this with many other forms of multiples, divisions, additions, and subtractions.