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Math Help - Can anyone help me?

  1. #1
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    Red face Can anyone help me?

    A mug is 1/6 full of milk. If 565ml are added, the mug will be full. How much does the mug hold? Can someone help me find the solution?
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by angelmt View Post
    A mug is 1/6 full of milk. If 565ml are added, the mug will be full. How much does the mug hold? Can someone help me find the solution?
    Let M represent the amount of milk the mug can hold.

    So we can set up the following equation:

    \underbrace{\frac{1}{6}M}_{\text{amount originally in mug}}+\underbrace{565}_{\text{amount added to mug}}=\underbrace{M}_{\text{total amount mug can hold}}

    Now, solving for M, we have 565=\frac{5}{6}M\implies M=\dots

    Can you finish the problem?
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  3. #3
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    Hello, angelmt!

    I don't suppose you made a sketch . . .


    A mug is 1/6 full of milk.
    If 565 ml are added, the mug will be full.
    How much does the mug hold?
    Code:
      -   *-------*   -
      :   |       |   :
      :   |       |   :
      :   |       |   :
      :   |  565  |   :
      C   |       | (5/6)C
      :   |       |   :
      :   |       |   :
      :   |       |   :
      :   * - - - *   -
      :   |///////| (1/6)C
      -   *-------*   -

    Let C = capacity of the mug (in ml).

    The bottom \tfrac{1}{6}C is filled with milk.

    The top \tfrac{5}{6}C contains 565 ml of milk.

    There is our equation: . \tfrac{5}{6}C \:=\:565

    Now solve for C . . .

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  4. #4
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    hello
    let x be what you're looking for
    x = \frac{5}{6} +\frac{1}{6},when you're mug is full.
    at the beginning the mug is \frac{1}{6} full,which means x equal only \frac{1}{6},and when you added 565 ml, x is \frac{1}{6} + 565ml,that is 565 = \frac{5}{6} = 5\times\frac{1}{6} and so \frac{1}{6} = \frac{565}{5} =113 ml.
    back to your x
    x = 113 + 565 = 678 ml
    Last edited by Raoh; July 10th 2009 at 10:43 AM.
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