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Math Help - Factoring

  1. #1
    Junior Member
    Joined
    Jul 2009
    Posts
    43

    Factoring

    im taking an online class and i just wanted to check my answers with someone...

    1. (21x to the fifth - 14x to the fourth - 35xsquared) =
    7xsquared (3x to the third - 2xsquared - 5)

    is that all? or is there more to the answer??

    2. (q squared +6q +9) =
    (q+3)(q+3)

    3. (t squared - 16t +64)=
    (t-8) squared

    and i have more...
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  2. #2
    Member
    Joined
    Mar 2009
    From
    Alberta
    Posts
    173
    Looks good to me, but another thing you can do with #2, is turn (q+3)(q+3)\rightarrow(q+3)^2, to be consistent with your #3 answer if you want; but your answers look perfectly fine to me!
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  3. #3
    Junior Member
    Joined
    Jul 2009
    Posts
    43
    Thanks :]

    1. (x squared -x -20) =0
    x=5,-4

    2. 2x squared = 7x +15
    x= -3/2, 5

    3. (2x +1) (x+3) = 42
    x= -13/2, 3

    4. (x) (x-5) = 66
    x= 11, -6
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  4. #4
    Super Member
    Joined
    May 2009
    Posts
    527
    1. (x squared -x -20) =0
    x=5,-4
    \begin{aligned}<br />
x^2 - x - 20 &= 0 \\<br />
(x - 5)(x + 4) &= 0 \\<br />
x &= 5 \\<br />
x &= -4<br />
\end{aligned}
    Correct!

    2. 2x squared = 7x +15
    x= -3/2, 5
    \begin{aligned}<br />
2x^2 = 7x + 15 \\<br />
2x^2 - 7x - 15 &= 0 \\<br />
(2x + 3)(x - 5) &= 0 \\<br />
x &= -3/2 \\<br />
x &= 5<br />
\end{aligned}
    Correct!

    3. (2x +1) (x+3) = 42
    x= -13/2, 3
    \begin{aligned}<br />
 (2x +1) (x+3) &= 42 \\<br />
2x^2 + 7x + 3 &= 42 \\<br />
 2x^2 + 7x - 39 &= 0 \\<br />
  (2x^2 + 13)(x - 3) &= 0 \\<br />
   x &= -13/2 \\<br />
 x &= 3<br />
 \end{aligned}
    Correct!

    4. (x) (x-5) = 66
    x= 11, -6
    \begin{aligned}<br />
  x(x - 5) &= 66 \\<br />
x^2 - 5x &= 66 \\<br />
  x^2 - 5x - 66 &= 0 \\<br />
(x - 11)(x + 6) &= 0 \\<br />
    x &= 11 \\<br />
  x &= -6<br />
  \end{aligned}
    Correct!


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