# Functions

Printable View

• Jul 9th 2009, 10:33 AM
A Beautiful Mind
Functions
I don't know where I'm going with this. I think my reasoning is out of whack, can someone please explain this to me?

http://img3.imageshack.us/img3/4803/43706846.jpg
Alright, so when f(x)=3, the x is a 1. And when x is a one over at the g(x) side where x is, it's a -1. So -1 x 3 = -3...B.
• Jul 9th 2009, 10:41 AM
Kasper
Quote:

Originally Posted by A Beautiful Mind
I don't know where I'm going with this. I think my reasoning is out of whack, can someone please explain this to me?

http://img3.imageshack.us/img3/4803/43706846.jpg
Alright, so when f(x)=3, the x is a 1. And when x is a one over at the g(x) side where x is, it's a -1. So -1 x 3 = -3...B.

We aren't looking for when $f(x)=3$, we are looking for the value of $f(x)$ AT $x=3$ Look at the table, and at $x=3$ we see that $f(x)=2$ which means that $f(3)=2$. Now because we have $g(f(3))$, we need to find $g(x)$ AT $f(3)=2$. So the question is essentially asking for $g(2)=?$

Looking at the table we see that $g(f(3))=g(2)=-3$ which is answer choice B.

Is another way to look at it.
• Jul 9th 2009, 10:44 AM
A Beautiful Mind
Nah, I got it. Thanks. ;)