# Math Help - Basic Factoring Question

1. ## Basic Factoring Question

Although it this is basic it has been a stumbling block for me.

Factor
$2x^2-32$

The answer is $2(x-4)(x+4)$ apparently. Would someone please show me how to solve this? Thanks

2. $2x^2-32 = 2(x^2-16) = 2(x^2-4^2) = 2(x-4)(x+4)$

3. $2x^2-32=2(x^2-16)=2(x^2-4^2)=2(x-4)(x+4)$

Use the formula $a^2-b^2=(a-b)(a+b)$