Basic Factoring Question

• July 8th 2009, 10:45 AM
allyourbass2212
Basic Factoring Question
Although it this is basic it has been a stumbling block for me.

Factor
$2x^2-32$

The answer is $2(x-4)(x+4)$ apparently. Would someone please show me how to solve this? Thanks
• July 8th 2009, 10:50 AM
SENTINEL4
$2x^2-32 = 2(x^2-16) = 2(x^2-4^2) = 2(x-4)(x+4)$
• July 8th 2009, 10:51 AM
red_dog
$2x^2-32=2(x^2-16)=2(x^2-4^2)=2(x-4)(x+4)$

Use the formula $a^2-b^2=(a-b)(a+b)$