hello. i need to add square root (25)+square root (24)+square root (21)+square root (16)+square root (9). Please can i get this answer in radical form and true form because i do not know how. thanxs a lot. also please xplain the process.

2. Originally Posted by OnMyWayToBeAMathProffesor
hello. i need to add square root (25)+square root (24)+square root (21)+square root (16)+square root (9). Please can i get this answer in radical form and true form because i do not know how. thanxs a lot. also please xplain the process.
$\sqrt{25}=5$

$\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}$

$\sqrt{21}=\sqrt{3\cdot 7}$ (Not simplified)

$\sqrt{16}=4$

$\sqrt{9}=3$
$12+2\sqrt{6}+\sqrt{21}$

3. ## replay to perfect hacker

is that the simplest form? 12+ 2 square root (6)+ square root (21)? also if i wanted to multiply that by 4 how would i proceed? thanxs a lot again.

4. Originally Posted by OnMyWayToBeAMathProffesor
is that the simplest form? 12+ 2 square root (6)+ square root (21)? also if i wanted to multiply that by 4 how would i proceed? thanxs a lot again.
Yes.
Unless you want to write,
$12+2\sqrt{3}\cdot \sqrt{2}+\sqrt{3}\cdot \sqrt{7}$
Thus,
$12+\sqrt{3}(2\sqrt{2}+\sqrt{7})$

5. ## My Kids are now asking me questions I can no longer answer

how do I do the following.

Square Root of 48 -Square Root of 75 +Square Root of 12.

The 75 is throwing me.

Many thanks for all your help.

I Used 2 Know This.

6. Originally Posted by Iused2KnowThis
how do I do the following.

Square Root of 48 -Square Root of 75 +Square Root of 12.

The 75 is throwing me.

Many thanks for all your help.

I Used 2 Know This.
$\sqrt{75} = \sqrt{3 \cdot 25} = \sqrt{3} \sqrt{25} = 5 \sqrt{3}$

7. Thats what I done, but how do a put 5 x Square root 3 back into the equation, when the other answers are based around square root of 12

I looked at the answer at the back of the book and answer is Square Root 3.

Thanks

8. Originally Posted by Iused2KnowThis
Thats what I done, but how do a put 5 x Square root 3 back into the equation, when the other answers are based around square root of 12

I looked at the answer at the back of the book and answer is Square Root 3.

Thanks
$\sqrt{48} = 4 \sqrt{3}$ and $\sqrt{12} = 2 \sqrt{3}$ by the same method as before.

so you have $4 \sqrt{3} - 5 \sqrt{3} + 2 \sqrt{3}$