Simple Math "Progression" - Need Smart People Help

Hello Everyone,

Thanks for viewing this and hopefully helping me out with this problem...

I'm writing a report on roulette and I need help figuring out a betting progression.

The minimum bet is $5, and the maximum bet is $500.

The "Martingale" theory is doubling your bet (playing black or red) until you win. However, I need a more mathematically correct betting progression.

So the question is, what betting progressions can survive 8 or more spins?

Here is an example of one betting progression that lasts 8 spins but does not hit the $500 limit (the next bet would be above the limit), and does not yield a profit, only breaks even)

$5
$5
$10
$20
$50
$100
$200
$400

The main progression I am looking for is the one that lasts 8 spins, and yields the highest profit!

Thank you so much to whoever can figure this out for me, as I'm absolutely horrible at math!

Thank you!

It's not clear to me what you are looking for here. Obviously, the progression that gives the biggest profit would be one where you win every time. In such a progression you would bet, and win, $5 on every spin. Of course, you can't control that- that's the whole point.

Hi,

Here's an example: (betting on red or black, which pays 1 to 1)

Bet 1 $5 - Lose
Bet 2 $5 - Lose
Bet 3 $10 - Lose
$20
$50
$100
$200
Bet 8 $400 - Win!

So that betting progression allows 8 spins before you hit the max bet, as the 9th bet would be above $500 which is not allowed. The reason for the two $5 bets at the start is we're betting to either make a profit, or break even.

If you bet $5 and win, the next bet would be $5. Only applying the progression on a loss bet.

So again to clarify, I seek to know the best betting progression between $5 and $500 that will last 8 spins, and is the most profitable when you hit a win... assuming it could hit any time.

Hope that makes sense!

Quote:

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Originally Posted by McMoney

Hi,

Here's an example: (betting on red or black, which pays 1 to 1)

Bet 1 $5 - Lose
Bet 2 $5 - Lose
Bet 3 $10 - Lose
$20
$50
$100
$200
Bet 8 $400 - Win!

So that betting progression allows 8 spins before you hit the max bet, as the 9th bet would be above $500 which is not allowed. The reason for the two $5 bets at the start is we're betting to either make a profit, or break even.

If you bet $5 and win, the next bet would be $5. Only applying the progression on a loss bet.

So again to clarify, I seek to know the best betting progression between $5 and $500 that will last 8 spins, and is the most profitable when you hit a win... assuming it could hit any time.

Hope that makes sense!

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The betting strategy with the highest expected return is almost certainly:

$0,$0,$0,$0,$0,$0,$0,$0.

with and expected win of $0.

CB

Quote:

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Originally Posted by CaptainBlack

The betting strategy with the highest expected return is almost certainly:

$0,$0,$0,$0,$0,$0,$0,$0.

with an expected win of $0.

CB

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Well put, Captain!

McMoney, I don't understand your point. Yes, what you give is a possible progression but you asked for the "best betting progression" which you can't control. The best possible 8 be progression would be to win all 8 bet, thus winning 8(5)= $40, as I said. But, again, you cannot control that. Using the system you describe, your bets depend on what happens with the wheel- you can't control it. As Captain Black suggests, the best expected outcome is given by turning your back on the roulette wheel and walking out of the casino!