How could I work out the following problem? I know it's an easy concept, but I cannot seem to grasp it. An explanation would be most appreciated.
What is the ratio of the area of the triangle DEC to the area of the rectangle ABCD?
How could I work out the following problem? I know it's an easy concept, but I cannot seem to grasp it. An explanation would be most appreciated.
What is the ratio of the area of the triangle DEC to the area of the rectangle ABCD?
Hello JadeKiaraThe triangle's area is one-half of the area of the rectangle.
The height of the triangle is the length of the line from E to the base, DC produced. And this is equal in length to BC and to AD.
So the area of the triangle is 1/2 base x height, which is 1/2 DC x AD. And of course, this is 1/2 the area of the rectangle.
Grandad