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Math Help - A simple ratio problem

  1. #1
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    A simple ratio problem

    How could I work out the following problem? I know it's an easy concept, but I cannot seem to grasp it. An explanation would be most appreciated.

    What is the ratio of the area of the triangle DEC to the area of the rectangle ABCD?
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  2. #2
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    Hello JadeKiara
    Quote Originally Posted by JadeKiara View Post
    How could I work out the following problem? I know it's an easy concept, but I cannot seem to grasp it. An explanation would be most appreciated. So the ratio is 1:2.

    What is the ratio of the area of the triangle DEC to the area of the rectangle ABCD?
    The triangle's area is one-half of the area of the rectangle.

    The height of the triangle is the length of the line from E to the base, DC produced. And this is equal in length to BC and to AD.

    So the area of the triangle is 1/2 base x height, which is 1/2 DC x AD. And of course, this is 1/2 the area of the rectangle.

    Grandad
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