Thread: Perimeter Problem

AE = 5 cm = base of a triangle. The other 2 sides are equal to 4 cm. Show, by calculation, that FX = 3.12 cm (correct to 2 decimal places), where FX is the height of a triangle (and the angle is 90 degrees).

Thank you for your help.

Hello JadeKiara

Originally Posted by JadeKiara

AE = 5 cm = base of a triangle. Show, by calculation, that FX = 3.12 cm (correct to 2 decimal places), where FX is the height of a triangle.

Thank you for your help.

This is clearly incomplete. Can we have the whole question please?

Grandad

Well, I know the height of a triangle is found by: a^2 = b^2 + c^2.
How can I show, by calculation, that FX = 3.12 cm (correct to 2 decimal places), where FX is the height of a triangle?

So, if the base is 5 cm, and each of the other two sides are 4cm, then you would draw a vertical line from the centre of the base to the vertex. Then using Pythagorus you would have which

When = FX, = 4cm, and = 2.5cm (half the base).

Ah! How silly of me! I forgot to halve the 5!

Haha. An easy mistake to make