AE = 5 cm = base of a triangle. The other 2 sides are equal to 4 cm. Show, by calculation, that FX = 3.12 cm (correct to 2 decimal places), where FX is the height of a triangle (and the angle is 90 degrees).
Thank you for your help.
AE = 5 cm = base of a triangle. The other 2 sides are equal to 4 cm. Show, by calculation, that FX = 3.12 cm (correct to 2 decimal places), where FX is the height of a triangle (and the angle is 90 degrees).
Thank you for your help.
So, if the base is 5 cm, and each of the other two sides are 4cm, then you would draw a vertical line from the centre of the base to the vertex. Then using Pythagorus you would have $\displaystyle c=\sqrt{4^2-2.5^2}$ which $\displaystyle \approx 3.12$
When $\displaystyle c$ = FX, $\displaystyle a$ = 4cm, and $\displaystyle b$ = 2.5cm (half the base).