If the roots of $\displaystyle 2x^4+8x^3+px^2+qx+r=0$ are -1, 1, 3, find the values of p, q,r

cant seem to get the right answer, i thought the last root must be 1 because the sum of the roots must be 4 (8/2) cept the answers say that p=-44, q=-8, r=42 which doesnt work for me ><""

AND

Show that the equation $\displaystyle x^4+x^3+x+1=0$ has a double root at x=-1. Hence show that there are no other real roots.