(2x+1)(2x+3)(x+3)(x+4)=300 problem is that i could not conclude this problem
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Originally Posted by vungaralas (2x+1)(2x+3)(x+3)(x+4)=300 problem is that i could not conclude this problem Expand the left hand side and re-arrange the equation into the form quartic = 0. The quartic factorises as $\displaystyle (x - 1)(2x + 11)(2x^2 + 9x+24)$. The details are left for you to do. Please show your full working and where you get stuck if you need more help.
i re-arranged the lhs like (2x+1)(x+4) (2x+3)(x+3) and in process i get common terms that i assume as a that will become as (a+2)( a+3)
Originally Posted by vungaralas i re-arranged the lhs like (2x+1)(x+4) (2x+3)(x+3) and in process i get common terms that i assume as a that will become as (a+2)( a+3) This makes no sense. Go back and read what I suggested that you do.
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