If a,b,c,x,y,z are real quantities and (a+b+c)^2 =3(bc+ca+ab)-3(x^2+y^2+z^2),then a=b=c a+b+c=0 x=y=z=0 none
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Originally Posted by vungaralas If a,b,c,x,y,z are real quantities and (a+b+c)^2 =3(bc+ca+ab)-3(x^2+y^2+z^2),then a=b=c a+b+c=0 x=y=z=0 none Where are you getting these? No one of these is sufficient but it is correct if a= b= c and x= y= z= 0.
Originally Posted by vungaralas If a,b,c,x,y,z are real quantities and (a+b+c)^2 =3(bc+ca+ab)-3(x^2+y^2+z^2),then a=b=c a+b+c=0 x=y=z=0 none Vague, is that how its worded in the original? CB
If a,b,c,x,y,z are real quantities and (a+b+c)^2 =3(bc+ca+ab)-3(x^2+y^2+z^2),then 1.a=b=c 2.a+b+c=0 3.x=y=z=0 4.none
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