Originally Posted by

**THSKluv** the question was to find the roots of this equation

$\displaystyle 8x^4-2x^3-27x^2+6x+9$

when two of the roots equalled zero.

so i let the roots be $\displaystyle \alpha, \beta, \gamma, \delta$

therefore $\displaystyle \alpha+\beta = 0$

i used the standard sum of roots, product of roots etc technique to work out simultaneous equations and i ended up with this result

$\displaystyle -2\alpha^2\gamma + 8\alpha^2\gamma^2 = 9$

$\displaystyle -8\alpha^2+2\gamma-8\gamma^2=-27$

$\displaystyle -4\alpha^2\gamma-\alpha^2+4\alpha\gamma^2=-3$

i'm not realli sure if those equations are correct but if they are, i dont realli no how to proceed to figure out gamma and alpha

if anyone could help me, i would realli realli appreciate it !!! thankyou !!