# Thread: Setting up and solving equations involving percentages

1. Originally Posted by illeatyourxface
wait what am i multiplying? 12,400 or 9,600??

im confused again
that's for checking your answers. you found x, so going back to your basic equations, just plug the values of x for the equations and you'll find the profit.

2. Originally Posted by yeongil
No, you already found the amount of each investment, $9,600 and$12,400. When you were asking about multiplying by 0.07 & 0.02, I thought you were checking your work.

Multiplying $9,600 by 0.07 gives the profit made from the first investment, which is$672.
Multiplying $12,400 by 0.02 gives the profit made from the second investment, which is$248.
Adding the two profits together gives us the $920 that we needed. Please reread my posts carefully, particularly post #11 (which I quote above). Thanks. 01 3. ohhh okay i see! sorry about that, im a little fustrated, i have another similar problem...here a man invested a total of$3,000 in 2 investments. he made a profit of 3% on the first investment and 4% on the second investment. if his total profit was $107, what was the amount of each investment? soooo im gonna try and set it up... 1st investment: .03x 2nd investment: .04( 3,000 -x) ??? 4. Originally Posted by illeatyourxface ohhh okay i see! sorry about that, im a little fustrated, i have another similar problem...here a man invested a total of$3,000 in 2 investments. he made a profit of 3% on the first investment and 4% on the second investment. if his total profit was $107, what was the amount of each investment? soooo im gonna try and set it up... 1st investment: .03x 2nd investment: .04( 3,000 -x) ??? correct! 5. and then the equation is .03x + .04(3,000- x) =107 and x = 1,300 and then 3,000- 1,300 = investment 2 = 1,700? 6. Originally Posted by illeatyourxface and then the equation is .03x + .04(3,000- x) =107 and x = 1,300 and then 3,000- 1,300 = investment 2 = 1,700? Correct! you have mastered this! 7. thank you so much! 8. Originally Posted by illeatyourxface ohh wait i think i get it! the$9600 is the profit and thats why you subtract it from $22000. and then we get$12,400 and the we find each investment by multiplying it by .07 and .02?

is that correct?
$9600 is the first investment profit from first investment=.07*$9600=\$672

Similarly, find for the other investment

EDIT: I forgot to refresh the window....so this was posted

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