# Thread: help with word problem (equation setup)

1. ## help with word problem (equation setup)

The ratio of two numbers in 5/4 and the first number is 7 more than the second number. to determine each of these numbers let x be the first number.
a)since the first number is 7 more than the second number and since the first number is x, what is the second number?
b)write a formula for the fraction (ratio) consisting the first number divided by the second number.
c) write an equation that says that this fraction (ratio) is 5/4.
d) solve the equaton
e) what are the two numbers

2. Originally Posted by illeatyourxface
The ratio of two numbers in 5/4 and the first number is 7 more than the second number. to determine each of these numbers let x be the first number.
a)since the first number is 7 more than the second number and since the first number is x, what is the second number?
b)write a formula for the fraction (ratio) consisting the first number divided by the second number.
c) write an equation that says that this fraction (ratio) is 5/4.
d) solve the equaton
e) what are the two numbers
Well, if the smaller number is x and the other number is x+7, I can set up the following ratio

$\displaystyle \overbrace{\frac{x+7}{x}}^\text{first number over second number}=\frac{5}{4}$

3. how would you solve the equation?

4. Originally Posted by illeatyourxface
how would you solve the equation?
Cross multiply, move x terms to one side of the eqution and constants to the other, combine like terms, and then divide each side by the coefficient of the variable.

5. is the answer 28?

6. Originally Posted by illeatyourxface
is the answer 28?

Yes it is!

7. thank you so much, im taking this online class for college and you are supposed to just do the problem in this workbook but there are no directions or steps or answers.... kinda fustrating and once again thanks for your help!

8. Originally Posted by illeatyourxface
thank you so much, im taking this online class for college and you are supposed to just do the problem in this workbook but there are no directions or steps or answers.... kinda fustrating and once again thanks for your help!
You are doing the right thing by asking for help here. You will score very high, and with people here like malaygoel and myself, you will get a better understanding of math in general.

9. thank youuuu! im gonna need a lot of help though

10. Originally Posted by illeatyourxface
thank youuuu! im gonna need a lot of help though
I'll keep helping you as long as you promise not to eat my face!

11. Originally Posted by VonNemo19
I'll keep helping you as long as you promise not to eat my face!
hahaha i wont eat your face, haha i just used my screename as this name cause idk what else to put