Hi,
how can I solve a quadratic equation where a is not equal to one.
ex:
$\displaystyle 2y^2 +y-1=0$
P.s: I want the fastest method
thx in advance
Sure it does. What numbers should I use so that
Remember, when factoring, the thing still has to preserve equality. You know how to foil right? You've got to do the reverse process here. It takes some practice, but one you get good at it, your life will be much easier.
Try this. Let the question marks be equal to 1. Multiply it out to verify that you have factored correctly. Then, ask yourself, what values of y will make $\displaystyle (2y-1)(y+1)=0$