In general we have :
here you have and
you do the math
how many moles of Al(NO3)3 would be contained in a 15.5 cc sample of a 0.250 M Al(NO3)3 solution> ? ok now will i need to get the atom mass of the element to use in this problem? will i use the mole 6.022 x1023?
how will it write it. i am online chemistr but lab 6 hrs on monday. only see teacher for those 6 hrsx. but busi with lab and no time for problem solving
For this question you do not need to use Avogadro's number because it's asking for a value of moles rather than molecules. You do not need the atomic mass of either since the question asks for the moles and the formula used give you a molar answer.
To solve this you may either use the method outlined in post 2 or you can use the formula:
- is the number of moles
- is the molarity in
- is the volume in
Plugging in the numbers gives: