Demonstrate:

Thank You.

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- Jun 28th 2009, 06:11 AMira069A solution without Newton's binom?
Demonstrate:

Thank You. - Jun 28th 2009, 10:54 PMGrandadMore information please
Hello ira069

Welcome to Math Help Forum!I think we need a bit more information here.

This statement clearly isn't true for all values of and . For instance, if and is an integer, depending upon whether is even or odd. Clearly for , this is greater than .

So I'm not really sure what the question means.

Grandad - Jun 28th 2009, 11:46 PMira069Thank you.
Thank you.

I am asking for a solution without Newton's binom,

for k integer positive, -2 < a < 2. - Jun 29th 2009, 12:48 AMProve It