4p + 4pq + pq^2 + 2p^2 + p^2q + 4q + 2q^2-16pq / q(p+2)

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- Jun 25th 2009, 04:07 AM #1

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- Jun 25th 2009, 05:52 AM #2

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That's an "expression", not a "problem"! It only becomes a problem when you are told to do something with it- and I don't see that here. What are you supposed to do? And is that final q(p+2) dividing only -16pq or is it dividing the entire expression to the left (in which case you should have parentheses)?

- Jun 25th 2009, 06:08 AM #3

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Hi the undertaker,

Is the problem simplify the following?

$\displaystyle \frac{4p + 4pq + pq^2 + 2p^2 + p^2q + 4q + 2q^2-16pq}{q(p+2)}$

If so note that

$\displaystyle q(p+2)^2=p^2+4pq+4q$

$\displaystyle q^2(p+2)=pq^2+2q^2$

$\displaystyle 2p(p+2)=2p^2+4p$

and so the expression becomes

$\displaystyle \frac{q(p+2)^2+q^2(p+2)+2p(p+2)-16pq}{q(p+2)} = q+p+2+\frac{2p}{q}-\frac{16p}{p+2}$

But perhaps that can be simplified more...