Solve the linear systems using substitution
y=x+1
y=2x-4
y=x+1
y=2x-4
Solve the linear systems using elimination
6x+3y=27
-6x+2y=-2
4x+3y=21
4x-5y=29
Could someone please explain substitution and elimination for me, thanks for your help.
Solve the linear systems using substitution
y=x+1
y=2x-4
y=x+1
y=2x-4
Solve the linear systems using elimination
6x+3y=27
-6x+2y=-2
4x+3y=21
4x-5y=29
Could someone please explain substitution and elimination for me, thanks for your help.
Since y= x+1 in the first equation, substitute x+1 for y in the second equation: y= x+ 1= 2x- 4. Now solve x+ 1= 2x-4 for x and then use y= x+1 to get x.
??? This is the same pair of equations!y=x+1
y=2x-4
Adding the two equations eliminates x:Solve the linear systems using elimination
6x+3y=27
-6x+2y=-2
(6x+ 3y)+ (-6x+ 2y)= 27+ (-2)
(6x- 6x)+ (3y+ 2y)= 27- 2
5y= 25
Solve for y and then replace y by that number in either equation to find x.
Subtract one equation from the other:4x+3y=21
4x-5y=29
(4x+3y)- (4x-5y)= 21- 29
(4x- 4x)+ (3y-(-5y)= 21- 29
8y= -8.
Could someone please explain substitution and elimination for me, thanks for your help.
Try some online lessons.