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Math Help - Factoring Quadratic Equation?

  1. #1
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    Factoring Quadratic Equation?

    Just re-learning the quadratic equation.

    I understand it until the end where the example in my book shows when solving:

    x= \dfrac {-4\pm2\sqrt{6}}{4}

    Then:

    x= -1- \dfrac {\sqrt{6}}{2} or, x=-1+\dfrac {\sqrt{6}}{2}

    Not quite sure how they factored, it does not explain. I tried, but kept coming up with.

    x= -2  \pm \dfrac {\sqrt{6}}{2}

    Somebody care to explain how it's done properly..
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  2. #2
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    What is the value of four divided by four?
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  3. #3
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    Quote Originally Posted by stapel View Post
    What is the value of four divided by four?
    It's 1.

    Wouldn't that cancel out the denominator?

    leaving,

    x=-1\pm2\sqrt{6}
    Last edited by NotSoBasic; June 20th 2009 at 03:02 PM.
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  4. #4
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    Quote Originally Posted by NotSoBasic View Post
    It's 1.

    Wouldn't that cancel out the denominator?

    leaving,

    x=-1\pm2\sqrt{6}
    <br />
x= \dfrac {-4\pm2\sqrt{6}}{4} = \frac{-4}{4} \pm \frac{2\sqrt6}{4}<br />

    Now what does 4/4 and 2/4 equal
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  5. #5
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    Ah, OK. That makes sense.. =D

    Is that step called something where you separate the values, I would like to research more on that.
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  6. #6
    Senior Member Stroodle's Avatar
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    It's called reducing, or simplifying, fractions.
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  7. #7
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by NotSoBasic View Post
    Ah, OK. That makes sense.. =D

    Is that step called something where you separate the values, I would like to research more on that.
    I'm not sure about what it's called, but I can prove it.

    \frac{a+b}{c}=\frac{1}{c}\cdot(a+b)=\frac{a}{c}+\f  rac{b}{c}
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