Originally Posted by

**yeongil** On the right side, are the x's in the numerator or the denominator? In other words, is it this:

$\displaystyle (1 + x)^{1/2} = 1 + \frac{1}{2}x - \frac{1}{8}x^2 $

or this:

$\displaystyle (1 + x)^{1/2} = 1 + \frac{1}{2x} - \frac{1}{8x^2} $?

Regarding the left side, how about the following -- would this work?

$\displaystyle \begin{aligned}

\sqrt{12} &= (16 \cdot 0.75)^{1/2} \\

&= (16(1 - 0.25))^{1/2} \\

&= 4(1 + 1/2 x - 1/8 x^2)\;\;\text{(plug in -0.25 for x?)}

\end{aligned}$

so x = -0.25 (or -1/4)?

01