1. ## Inequality:

Show that $e^n>\frac{(n+1)^n}{n!}$ where n is an integer

2. boy, do I suck at this stuff.

This cant be done by induction?

It holds for n = 1.

Assume it holds for n=k, prove it holds for n=k+1.

$e^{k+1}=e^{k}\cdot e > \frac{(k+1)^{k}}{k!} \cdot e$

I´m not saying this is correct at all, just giving some thoughts! =)