Results 1 to 3 of 3

Math Help - EAsy algebra question need help!!!

  1. #1
    Newbie
    Joined
    May 2009
    Posts
    12

    EAsy algebra question need help!!!

    PLease help !

    -(y/2 + 1/16)=3(y/16 - 1/12)
    PLease explain!!

    1/6[1/2(1-2n)+1/3]=n/3
    Please explain!!!!!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor Amer's Avatar
    Joined
    May 2009
    From
    Jordan
    Posts
    1,093
    Quote Originally Posted by econlover View Post
    PLease help !

    -(y/2 + 1/16)=3(y/16 - 1/12)
    PLease explain!!

    1/6[1/2(1-2n)+1/3]=n/3
    Please explain!!!!!
     - (\frac{y}{2} + \frac{1}{16} ) = 3(\frac{y}{16} - \frac{1}{12} )

    \frac{-y}{2} + \frac{-1}{16} =\frac{3y}{16} - \frac{3}{12}

    \frac{-y}{2} + \frac{-1}{16} =\frac{3y}{16} - \frac{1}{4}

    \frac{3y}{16} + \frac{y}{2} = \frac{-1}{16} + \frac{1}{4}

    \frac{3y}{16} + \frac{8y}{16} = \frac{-1}{16} + \frac{4}{16}

     \frac{11y}{16} = \frac{3}{16}

    \frac{11y}{16} =\frac{3}{16}

     y =\frac{3}{11}

    show us your work in the second one
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member
    Joined
    May 2009
    Posts
    527
    Um, Amer, the OP made a duplicate thread. Look here: http://www.mathhelpforum.com/math-he...need-help.html



    01
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Easy Linear Algebra Question
    Posted in the Advanced Algebra Forum
    Replies: 2
    Last Post: September 12th 2010, 01:57 PM
  2. Easy algebra question - Quotient rule.
    Posted in the Algebra Forum
    Replies: 2
    Last Post: May 2nd 2010, 01:37 AM
  3. Seemingly easy question... too easy.
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: August 23rd 2009, 09:36 PM
  4. Easy algebra question need help!!!
    Posted in the Algebra Forum
    Replies: 3
    Last Post: June 18th 2009, 06:01 AM
  5. Easy algebra
    Posted in the Algebra Forum
    Replies: 1
    Last Post: March 4th 2008, 03:19 AM

Search Tags


/mathhelpforum @mathhelpforum