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Math Help - Some basic algebra equations

  1. #1
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    Some basic algebra equations

    Again, to fly through the afternoon, I've given the team some more maths to keep their brains bubbling!

    Could someone please provide for the answers and working for the following:



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  2. #2
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    A)
    \begin{aligned}<br />
x(x + 4) &= 21 \\<br />
x^2 + 4x &= 21 \\<br />
x^2 + 4x - 21 &= 0 \\<br />
(x + 7)(x - 3) &= 0 \\<br />
x + 7 &= 0\;\;\Rightarrow\;\; x = -7 \\<br />
x - 3 &= 0\;\;\Rightarrow\;\; x = 3<br />
\end{aligned}


    B)
    \begin{aligned}<br />
\frac{x - 1}{3} - \frac{x - 1}{2} &= 6 \\<br />
6\left(\frac{x - 1}{3} - \frac{x - 1}{2}\right) &= 6(6) \\<br />
2(x - 1) - 3(x - 1) &= 36 \\<br />
2x - 2 - 3x + 3 &= 36 \\<br />
-x + 1 &= 36 \\<br />
-x &= 35 \\<br />
x &= -35<br />
\end{aligned}


    01
    Last edited by mr fantastic; June 17th 2009 at 11:40 PM.
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  3. #3
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    Thanks for your response!

    Could someone please attempt the first section
    Last edited by mr fantastic; June 17th 2009 at 11:41 PM. Reason: Merged posts
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  4. #4
    Super Member Showcase_22's Avatar
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    (3x^2)^4=3^4x^8
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  5. #5
    Senior Member Stroodle's Avatar
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    (a)\;9xy+8y-4y^2 +9y-2x^2y=9xy+17y-4y^2 -2x^2 y

    (b)\;(3x^2)^4=3^4\times (x^2)^4=81x^8

    (c)\;\frac{24x^6 y^2}{6x^2 y}=\frac{4x^6y^2}{x^2 y}=4x^4 y

    (d)\;\frac{8x-6(2x+4)+10)}{8}=\frac{8x-12x-24+10}{8} \;=\frac{-4x-14}{8}=\frac{-2(2x+7)}{8}=-\frac{2x+7}{4}
    Last edited by Stroodle; June 18th 2009 at 07:16 PM. Reason: added working
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  6. #6
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    Thank you very much again!
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