x + y = 296
10x + 5y = 1910
x = 296 - y
10(296 - y) + 5y = 1910
2960 - 10y + 5y = 1910
2960 - 5y = 1910
-5y = -1050
y = 210
x = 296 - 210
x = 86
So, 86 adult tickets and 210 student tickets were sold.
01
There were 296 tickets sold for the school banquet. Adults tickets were 10$ and students were 5$. The receipts totalled $1910.
make up an equation for the total number of tickets sold and a equation for the total receipts sing x to represnt the number of adult tickets and y to represent the number of student tickets
using either subsitutution of elementation, solve the above system of equations to find the number of adult and student tickets that were sold for this banquet