Math Help - [SOLVED] How to solve this inequation?

1. [SOLVED] How to solve this inequation?

$1 + l x l > \frac{6}{l x l}$

lxl stands for modulus of x. Find the solution set

2. Consider cases. Obviously, x cannot equal zero, or you'll have division by zero.

If x > 0, then |x| = x, and you have 1 + x > 6/x, so x^2 + x - 6 > 0.

If x < 0, then |x| = -x, and you have 1 - x > -6/x, so 0 < x^2 - x - 6.

Solve the two quadratic inequalities.

3. Originally Posted by mark1950
$1 + l x l > \frac{6}{l x l}$
lxl stands for modulus of x. Find the solution set
Here is a second way.
That is $|x|+|x|^2>6$ then it follows that $|x|>2$.