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Math Help - [SOLVED] How to solve this inequation?

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    [SOLVED] How to solve this inequation?

     1 + l x l > \frac{6}{l x l}

    lxl stands for modulus of x. Find the solution set
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  2. #2
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    Consider cases. Obviously, x cannot equal zero, or you'll have division by zero.

    If x > 0, then |x| = x, and you have 1 + x > 6/x, so x^2 + x - 6 > 0.

    If x < 0, then |x| = -x, and you have 1 - x > -6/x, so 0 < x^2 - x - 6.

    Solve the two quadratic inequalities.
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  3. #3
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    Quote Originally Posted by mark1950 View Post
     1 + l x l > \frac{6}{l x l}
    lxl stands for modulus of x. Find the solution set
    Here is a second way.
    That is |x|+|x|^2>6 then it follows that |x|>2.
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